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          1. 博彥科技 2021 軟件面試題

            小編:管理員 569閱讀 2021.09.24

            第1題:

            a, b, c : wear cap(black or white, but not all white), a and b can see, but c is blink;? a,b,c in turn answer whether he can know what color he is wearing, a said no , b said no ,c said is :
            Q: why c know, and what color his is?


            第2題:

            100個和尚吃100個饅頭,大和尚一人吃4個,小和尚4人吃一個,
            問:大,小和尚各多少人?


            第3題:

            擴展名為DLL的動態鏈接文件的特點是_________
            A.? ?可以自由的插入到其他的源程序中使用
            B.? ?本身是一個數據文件,可以與其他程序動態的鏈接使用
            C.? ?本身可以獨立運行,也可以供其他程序在運行是調用
            D.? ?本身不能獨立運行,但可以供其他程序在運行時調用


            第4題:

            面向對象技術中,對象是類的實例,對象有三種成分______、屬性和方法(或操作)
            A.標識? ? ? ? B、規則? ? ? ? C、封裝? ? ? ? D、消息


            第5題:

            程序設計語言引入“類”的概念是為了解決數據保護問題,C++語言將類的成員封裝在類體之中,使之具有一定的存取規則,這些規則規定了存取類的成員的權力,其中,對于用private說明的成員,它_______
            A. 既能被該類的成員函數訪問,又能被外界直接訪問
            B. 只能被該類的成員函數訪問,外界不能直接訪問
            C.不能被該類的成員函數訪問,只能外界直接訪問
            D.既不能被該類成員函數訪問,也不能外界直接訪問


            第6題:

            ___________ is a set of specifications and software that allow small programs or software components to work together.
            A. ActiveX? ? ? B. XML? ? ? C. HTML? ? ? ? D.? DAMS


            第7題

            請簡要說明如何測試下面的程序?

            template
            void OutputRoots(T? a,? T? b ,? T? c)
            {
            T d=b * b – 4*a*c;
            if(d>0)
            {
            float sqrtd=sqrt(d);
            count <<”there are two real roots”
            <<(-b+sqrtd)/(2*a)
            <<”and”
            <<(-b-sqrtd)/(2*a)
            < }
            }
            Else if (d= =0) {
            Cout<<”there is only one distinct root”
            <<-b(2*a)
            < }
            else{
            cout <<”The roots are complex”
            < <<”The real part is”
            <<-b/(2*a)
            <<”The imaginary part is”
            < < }



            第8題:

            以下是一段用C編寫的函數,請指出其中存在的問題:
            1? int PtintDigit(void)
            2? {
            3? ? ? char*p;
            4? ? ? int i=0;
            5? ? ? p=(char*) malloc (256*sizeof (char));
            6? ? ? for (I=0;I<=256;I++,p++)*p=I;
            7? ? ? printf(Here is the numbers you need; %d\n”,i)
            8? ? ? }


            第9題:

            請翻譯下面這段文字
            For Chinese applicants,the first step in applying for a visa is to make an appointment by calling 65325305 or 65322228. The problem is that the two numbers are so busy that often they can’t get through . Mr Bennet explained :“Since all embassies have to use 6532 telephone prefix and the number of lines is limited, the US embassy is only allotted two lines for our appointment system. Insgroupsto solve the problem, we plan to work through a contractor. Contractors don’t have to use the 6532 prefix , so they can be assigned move lines and hire lots of people to answer calls . Applicants will also be able to use faxes and the Internet to make appointments, which will greatly enhance flexibility and convenience, Since the contact has not been awarded yet , I can’t say exactly when the new system will be operative-hopefully sometimes in the fall.”


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